Math, asked by kotourasan12374, 8 months ago

1. How many millimeters make one kilometer?
(a) 1000(b) 10,000(c) 100,000(d) 10,00,000
2. A box contains 500000 medicine tablets each weghinh 10 mg. what is the total weight of all the tablets in the box in kilograms?
(a) 5,00,000(b) 50,000(c) 5kg(d) 500kg
3. What is the difference between the greatest and the least number that can be written using the digits
6, 2,7,4,3, each only once?
(a) 50000(b) 52965(c) 52865(d) 51965
4. In the international system of numeration we can write One billion as:
(a) 1 crore(b) 10 crore(c) 100 crore(d) 1000 crore

5. Estimation of the quotient 86 ÷ 9 to nearest 10:
(b) 90(b)10(c)80(d) none of these

6. When 1787 is rounded off to nearest tens, we get:
(a) 1790(b) 1780(c) 1700(d)1800

7. The sum of the number 765432 and the number obtained by reversing its digit is:
(a) 930865(b) 980356(c) 999999(d) 9999998
8. The expanded form for 308927 is:
(a) 3000000 + 8000 + 900 + 20 + 7(b) 300000 + 800 + 90 + 2 + 7
(c) 30000 + 80000 + 9000 + 20 + 7(d) 300000 + 8000 + 900 + 20 + 7
9. Estimate 734+998 by rounding off the nearest tens:
(a) 1730(b) 1740(c) 1750(d) 1760
10. The difference between the face value and place value of 4 in 2416 is:
(a) 404(b) 396(c) 3000(d) 2996
11. Use the given digits and without repetition make the greatest and smallest 4-digit. numbers. (a) 2, 8, 7, 4 (b) 9, 7, 4, 1 (c) 4, 7, 5, 0 (d) 1, 7, 6, 2 (e) 5, 4, 0, 3
12. Population of Agra and Aligarh districts in the year 2001 was 36,20, 436 and 29,92,286, respectively. What was the total population of the two districts in that year?

13. Estimate the product 5981 × 4428 by rounding off each number to the nearest
(i) tens (ii) hundreds (iii) thousands.
If you will make it so I will mark you brainliest.

Answers

Answered by Swarup1998

1. Option (d) 10,00,000

1 kilometer = 1000000 millimeters

2. Option (c) 5 kilograms

Weight of all the tablets

= 500000 × 10 mg

= 5000000 mg

= (5000000 ÷ 1000000) kilograms

= 5 kilograms

3. Option (b) 52965

Greatest number = 76432

Least number = 23467

Difference = 76432 - 23467 = 52965

4. Option (c) 100 crore

One billion

= 1,000,000,000

= 100,00,00,000

= 100 crore

5. Option (b) 10

86 ÷ 9

= 9.555 ... ...

= 10

6. Option (a) 1790

1780 < 1787 < 1790

Here, 1787 - 1780 = 7 and 1790 - 1787 = 3

Since 3 < 7, round off to the nearest tens is 1790.

7. Option (c) 999999

The number = 765432

Reverse number = 234567

Sum = 765432 + 234567 = 999999

8. Option (d) 300000 + 8000 + 900 + 20 + 7

Now, 308927

= 3 × 100000 + 0 × 10000 + 8 × 1000 + 9 × 100 + 2 × 10 + 7 × 1

= 300000 + 8000 + 900 + 20 + 7

9. Option (a) 1730

734 becomes 730

998 becomes 1000

Thus required sum = 730 + 1000 = 1730

10. Option (b) 396

The number is 2416

Face value of 4 = 4, place value of 4 = 400

Difference = 400 - 4 = 396