Question

(1) How many natural numbers are there between 200 and 500 which are divisible by 7.
​

Answer 1

Step-by-step explanation:

First no. divisible by 7 b/w 200 and 500 = 203

Last no. divisible by 7 b/w 200 and 500 = 497

Difference between two consecutive terms (d) = 7

an = a + (n - 1)d

⇒ 497 = 203 + (n-1)7

⇒ 497 - 203 = 7n - 7

⇒ 294 + 7 = 7n

⇒ 301/7 =n

43 = n

43 numbers are divisible by 7 b/w 200-500.

Answer 2

Answer:

43

Step-by-step explanation:

the explanation is attached with the answer.

First you make A.P. of the numbers divisible by 7 between 200 and 500 and the solve them by formula of nth term