Question

1 How many numbers lies between 10 and 300
which when divided by 4
live a remender 3​

Answer 1

Answer:

A.P = , 11 , 15........

hence . a=11

d=4

tn=a+(n-1)×d

t300= 11 + (300 - 1 ) ×4

t300= 11 + 299 ×4

= 11 + 1196

= 11207

Answer 2

Answer:

73

Step-by-step explanation:

The number lies between 10 to 300 which when divided by 4 leaves the remainder 3 are,

11,15,19...299.

Clearly, it is an AP with first term,

a = 11, d = 4, last term = 299.

Let the are n terms in the given AP.

Then,

an = a + (n -1) * d

=> 299 = 11 + (n - 1) * 4

=> 299 = 11 + 4n - 4

=> n = 73.

Hence, there are 73 such terms.

Hope it helps!