Math, asked by diannanaig, 5 months ago

1. How many sixth in 3/12?
2. How many 1/6 are there in 20
3. How many 1 1/4 in there in 9
4. divided 4 1/2 by 2/3
5 2 1/3 divided by 4 2/3
show step by step please​

Answers

Answered by SWEETYASH
1

In the figure, two circles with centres O and O’ intersect each other at B and C.

ACD is a line, ∠AOB = 130°

Arc AB subtends ∠AOB at the centre O and ∠ACB at the remaining part of the circle.

∴ ∠ACB =12∠AOB

= 12 x 130° = 65°

But ∠ACB + ∠BCD = 180° (Linear pair)

⇒ 65° + ∠BCD = 180°

⇒ ∠BCD = 180°-65°= 115°

Now, arc BD subtends reflex ∠BO’D at the centre and ∠BCD at the remaining part of the circle

∴ ∠BO’D = 2∠BCD = 2 x 115° = 230°

But ∠BO’D + reflex ∠BO’D = 360° (Angles at a point)

⇒ x + 230° = 360°

⇒ x = 360° -230°= 130°

Hence x = 130°In circle with centre O

AB is chord of the circle, ∠OAB = 35°

In ∆OAB,

OA = OB (Radii of the circle)

∠OBA = ∠OAB = 35°

But in ∆OAB,

∠OAB + ∠OBA + ∠AOB = 180° (Angles of a triangle)

⇒ 35° + 35° + ∠AOB = 180°

⇒ 70° + ∠AOB = 180°

⇒ ∠AOB = 180°-70°= 110°

∴ Convex ∠AOB = 360° -110° = 250°

But arc AB subtends ∠AOB at the centre and ∠ACB at the remaining part of the circle.

∴∠ACB = 12∠AOB

⇒ x = 12 x 250° = 125°

∴ x= 125°

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