Question

1. How many tiles whose length and breadth
are 13cm and 7cm respectively are needed to
cover
rectangular region whose lengte &
breadth are 520 cm and 140 cm?
2. The length of a rectangular wooden board is thrice its width. If width of the board 120 cm find the cost of farming at the rate of dollar 5 for 20 cm..

Please help you will be marked as Brainliest.. ​

Answer 1

Answer:

1. 800 tiles

2. 240$

Step-by-step explanation:

1. First, let us calculate the area of the rectangular region, for this, we will use the formula for area of rectangle,

Area of the rectangle = l × b

= 520 × 140

= 72800 cm²

Now, we will find the area of one tile = 13 × 7

= 91 cm²

Number of tiles = Area of the rectangular region / Area of one tile

= 72800 / 91

= 800

So, the required number of tiles are 800.

2. Given that the length of the rectangular wooden board is thrice its width and the width is 120 cm, therefore,

length = 3 × width

length = 3 × 120

length = 360 cm

Now, we will find the perimeter of the board,

= 2(360 + 120)

= 2(480)

= 960 cm

The cost of framing 20 cm of the board is 5$.

Then, the cost of framing 960 cm of the board = 960/20 × 5

= 48 × 5

= 240 $ [answer]

Hope this helps you!!!!