Math, asked by bhaajam, 1 year ago

1) HOW MANY TIMES A WHEEL OF RADIUS 28 CM MUST ROTATE TO GO 352M ?? (TAKE PI =22/7)

Answers

Answered by NidhraNair
17
✔️Here the given values are :-

⭕️ total distance=352m

⭕️raidus of wheel=28m

⭕️circumference of wheel = 2 π r

=2 x 22/7 x r

=2 x 22/7 x 28

=2 x 22 x 4

=8 x 22

=176cm

⭕️distance covered in 1 rotation=176cm

⭕️no.of rotation of a wheel = total distance/distance covered in 1 rotation

=35200/176

=17600/88

=4400/22

=200

\huge\bf{\boxed {\red{\mathfrak{thank \: you :)}}}}
Answered by Anonymous
15

Total distance = 352m

Raidus of wheel = 28m

_______________ [ GIVEN ]

We know that..

》Circumference of wheel = 2\pir

=> 2 × \dfrac{22}{7} × r

Put the known values in above formula

=> 2 × \dfrac{22}{7} × 28

=> 2 × 22 × 4

=> 8 × 22

=> 176 cm

Distance covered in one rotation = 176 cm

Now..

Number of rotation of a wheel =

\dfrac{Total\: distance}{Distance \:covered \:in\: one \:rotation}

=> \dfrac{35200}{176}

=> 200

____________________________

200 times a wheel of radius 28 cm must rotate to go 352 m.

____________ [ ANSWER ]

____________________________

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