1. How much cloth was used for the floor of the tent?
a)31.6 m2 b) 16m2 c)10m2 220m2
2. What is the volume of the tent?
a) 300m3 6)160m3 c) 513.3m3 d)500m3
3. What is the area of the floor of the tent?
a)50 m2 b) 100m2 c)150m? d)154m2
4. What is the total surface area of the tent?
a)400 m2 b) 422.4m2 c)300m2 d)400m²
5. What is the slant height of the tent ?
a)12m b)12.2m c)15m d) 17m
Answers
Question :- Once four friends Rahul, Arun, Ajay and Vijay went for a picnic at a hill station. Due to peak season, they did not get a proper hotel in the city. The weather was fine so they decided to make a conical tent at a park. They were carrying 300 m² cloth with them. They made the tent with height 10 m and diameter 14 m The remaining cloth was used for the floor.
1. How much cloth was used for the floor of the tent ?
a)31.6m² b) 16m² c)10m² d) 20m² .
2. What is the volume of the tent ?
a) 300m³ 6)160m³ c) 513.3m³ d)500m³ .
3. What is the area of the floor of the tent ?
a) 50m² b) 100m² c)150m² d)154m²
4. What is the total surface area of the tent ?
a)400m² b) 422.4m² c)300m² d)400m²
5. What is the slant height of the tent ?
a) 12m b) 12.2m c) 15m d) 17m
Solution :-
given that,
- Height of conical tent = 10m .
- Diameter = 14m.
so,
- Radius = 14/2 = 7m.
then,
→ Slant height of the tent = √(r² + h²) = √(7² +10²) = √149
= 12.2 m (Ans.5)
now,
→ CSA of conical tent = π * r * slant height = (22/7) * 7 * 12.2
= 268.4m² .
then,
→ Cloth used for the floor of the tent = Total cloth area - CSA of conical tent = 300 - 268.4 = 31.6 m² (Ans.1)
also,
→ Volume of the tent = (1/3)πr²h = (1/3) * (22/7) * 7 * 7 * 10 = (1/3) * 22 * 70 = (1540/3) = 513.3 m³ (Ans.2)
and,
→ Area of the floor of the tent = π(radius)² = (22/7) * 7 * 7 = 154 m² (Ans.3)
therefore,
→ TSA of the tent = CSA + Area of the floor = 268.4 + 154 = 422.4 m² (Ans.4)
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Answer:
How much cloth was used for the floor of the tent?