Math, asked by yadavarshit221, 4 months ago

1. how much is the total distance between the sixes hit by Sachin and Sehwag .
2. what is the total distance of the sixes hit by Yuvraj and Virat .
3. how much long is the six hit by Sehwag than Virat.
4. How much long is the six hit by Sachin than Yuvraj.
5. the total distance of sixes hit by which two players is the most How much?
6. the total distance of sixes hit by which two players is the least How much?
please give me full answer ​

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Answers

Answered by prabhas24480
0

\huge\star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}⋆

Let the lowest score in one innings be x. Then,

Highest score in an innings = x + 172

Total runs in 40 innings = 40 x 50 = 2000

Total runs in 38 innings = 38 x 48 = 1824

Given, 2000 - {x + (x + 172)} = 1824

⇒ 1828 - 2x = 1824 ⇒ 2x = 4 ⇒ x = 2

∴ Highest score = 172 + 2 = 174

Answered by BrainlyFlash156
0

\huge \mathcal {\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}{!}}}

Let the lowest score in one innings be x. Then,

Highest score in an innings = x + 172

Total runs in 40 innings = 40 x 50 = 2000

Total runs in 38 innings = 38 x 48 = 1824

Given, 2000 - {x + (x + 172)} = 1824

⇒ 1828 - 2x = 1824

⇒ 2x = 4

⇒ x = 2

∴ Highest score = 172 + 2 = 174

HOPE SO IT WILL HELP......

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