1. How much potassium chlorate should be heated to produce 5.6L of oxygen at NTP? explain it completely!!
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2KClO3 ---> 2KCl + 3O2
so 122.5 x 2 = 245 g of KClO3 gives 3x 22.4 l of oxygen gas
therefore 5.6 l of oxygen gas will be produced by( 245/ 3x 22.4 )x 5.6 = 20.41g of potassium chlorate
so 122.5 x 2 = 245 g of KClO3 gives 3x 22.4 l of oxygen gas
therefore 5.6 l of oxygen gas will be produced by( 245/ 3x 22.4 )x 5.6 = 20.41g of potassium chlorate
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