Physics, asked by akhil365341, 1 year ago

1 How much work is required to carry a 6uC charge from the
positive terminal to the positive terminal of 9V battery?​

Answers

Answered by krithikasmart11
0

Answer:

Work is required to carry a 6uC charge from the positive terminal to the positive terminal of 9V battery is 54*10^-6J

Explanation:

To find : Work is required  to carry a 6uC charge from the positive terminal to the positive terminal of 9V battery.

Given: Charge (q) =6uC

                         battery (V)=9V

Solution: Work (w)=qV

                               =6*10^-6*9

                               =54*10^-6J

#SPJ3

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