Question

1) How times does the dicit a occur the numbers between 10 and 100?​

Answer 1

Step-by-step explanation:

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Answer 2

⇒  1–10 = 2 times

⇒  11–20 = 10 times

⇒  21–30 = 1 time

⇒  31–40 = 1 time

⇒  41–50 = 1 time

⇒  51–60 = 1 time

⇒  61–70 = 1 time

⇒  71–80 = 1 time

⇒  81–90 = 1 time

⇒  91–100 = 2 times

⇒  Total=2+10+1+1+1+1+1+1+1+2=21∴The digit 1 appear in number from 1 to 100 is 21.