Question

1. How will a gas velocity vary if its molecular weight was decreased from 144 g/mol to 64 g/mol?
2. How will a gas velocity vary if its molecular weight was increased from 32 g/mol to 128 g/mol?

Answer 1

Answer:

The volume of the container has decreased, which means that the gas molecules have to move a shorter distance to have a collision. i think idk

Explanation:

The explanation is the answer

Answer 2

Answer:

Explanation:

1. Given that, the gas velocity varies if its molecular weight was decreased from 144 g/mol to 64 g/mol.

$V_{rms}$ = $\frac{\sqrt{3RT} }{M}$

$V_{rms}$ is the root mean square velocity of gas molecules.

R is the molar gas constant

T is the temperature in kelvin

M is the molecular mass of gas

from the equation, we get the relation between velocity and molecular mass = V∝$\frac{1}{\sqrt{M} }$

$\frac{V2}{V1}$ = $\frac{\sqrt{144} }{\sqrt{64} }$×100 = $\frac{12}{8}$×100 = 150%

So, if we decrease from 144 g/mol to 64 g/mol the velocity will be increased by 150%.

2. molecular weight was increased from 32 g/mol to 128 g/mol.

$\frac{V2}{V1}$  = $\frac{\sqrt{32} }{\sqrt{128} }$ ×100 = 0.5×100 = 50%

So, if we increase from 32 g/mol to 128 g/mol the velocity will be decreased by 50%.