Question

1)How will the gravitational force change when their masses are doubled?

2)what is the distance covered of a free falling body during the first three seconds of fall

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Answer 1

Explanation:

1] According to Newton's formula for gravitational force:

F = (G M1 × M2)/(R^2)

where M1 and M2 are masses and R is the distance between the masses.

So, if their masses are doubled, then the force of gravity between them is increased 4 times. ie.

2M1 × M2 = 4M1 × M2

So, F=4(G×M1×M2)/(R^2)

where R is constant.

2] h = ut + (1/2) gt^2

Here, h = distance traveled by the body

u = starting velocity

t = time

g = gravitational acceleration

h = (0×3) + (1/2) × 9.8 × 3^2

h = 0 + 4.9 × 9

h = 44.1 m

Hence, it will fall 44.1 meters if there are no external force acting on it.