Question

(1+i)(1+i)(1+i) find a&b​

Answer 1

Answer:

$\Large\boxed{-2+2i}$

Step-by-step explanation:

Given:

To solve this problem, first you have to use the exponent rule and perfect cube formula.

Solutions:

First, you used exponent rule.

$\Large\boxed{\textnormal{EXPONENT RULES FORMULA}}$

$\displaystyle L^M*L^N=L^M^+^N$

$\displaystyle (1+i)(1+i)(1+i)=(1+i)^{1+1+1}$

Add the numbers from left to right.

$\displaystyle 1+1+1=3$

$\displaystyle (1+i)^3$

Used perfect cube formula.

$\Large\boxed{\textnormal{{PERFECT CUBE FORMULA}}}$

$\displaystyle (A+B)^3=A^3+3A^2B+3AB^2+B^3$

A=1

B=i

Rewrite the problem down.

$\displaystyle 1^3+3*1^2i+3*1*i^2+i^3$

Solve.

$\displaystyle 1^3+3*1^2i+3*1*i^2+i^3=\boxed{-2+2i}$

$\Large\boxed{-2+2i}$

So, the correct answer is -2+2i.