Question

(1+i/1-i)^2 state the value of a and b in form of a​

Answer 1

$( \frac{1 + i}{1 - i} ) {}^{2} \\ = (\frac{(1 + i)(1 + i)}{(1 - i)(1 + i)} ) {}^{2} \\ = (\frac{(1 + i) {}^{2} }{1 {}^{2} - i {}^{2} } ){}^{2} \\ = (\frac{1 {}^{2} + i {}^{2} + 2.1.i }{1 - ( -1 )}){}^{2} \\ = (\frac{1 - 1 + 2i}{2} ){}^{2} \\ = (\frac{2i}{2}){}^{2} \\ = i{}^{2} \\ = -1=-1+0(i)$

Answer 2

Answer:

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