Question

(1+i)(1-i) equals, here 'i'for iota

Answer 1

(1-i)(1+i)=1²-i² (i²=-1)
1+1=2
i-imaginary number

Answer 2

a+b×a-b=a^2-b^2
a=1 B=I
then
1^2-i^2. [i^2=-1]
1-(-1)
1+1=2