1. (i) 12x +15 (ii) 14m-21 (iii) 9n -12n 3 13,2
Answers
Answered by
1
Answer:
12x + 15
Taking 3 as common from the whole, we get,
12x + 15 = 3(4x + 5).
(ii) 14m – 21,
Taking 7 as common from the whole, we get,
14m – 21 = 7(2m – 3)
(iii) 9n – 12n2,
Taking 3n as common from the whole, we get,
9n – 12n2 = 3n (3 – 4n).
Answered by
0
Answer:
(i)12x + 15
=3(4x+5)
(ii)14m-21
=7(2m-3)
Step-by-step explanation:
sorry but the last question can not be defined
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