Question

(1+i)²⁰¹⁶/(1-i)²⁰¹⁴​

Answer 1

Step-by-step explanation:

$= \frac{ {(1 + i)}^{2016} }{ {(1 - i)}^{2014} } \\ = ( { \frac{1 + i}{1 - i} )}^{2014} \times ( {1 + i)}^{2} \\ = ( { \frac{1 + i}{1 - i} \times \frac{1 + i}{1 - i} )}^{2014} 2i \\ = {i}^{2014} .2i \\ = 2 {i}^{2} .i \\ = - 2i \\ \\ hope \: it \: will \: help \: you.$

Answer 2

Answer:

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