(1+i√2)^8+(1-i√2)^8
Answers
Answered by
0
Answer:
2
Step-by-step explanation:
(
2
1+i
)
8n
+(
2
1−i
)
8n
=[(
2
1+i
)
2
]
4n
+[(
2
1−i
)
2
]
4n
=(
(
2
)
2
2i
)
4n
+(
(
2
)
2
−2i
)
4n
=(i)
4n
+(−i)
4n
=1+1
=2
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