Math, asked by s28, 1 year ago

(1+i/√2)^8 + (1-i/√2)^8

Answers

Answered by narandermadi1
2
I think that can help you if it can help you than click the thanks button
Attachments:
Answered by rishabhsingh010
0
(1+I/√2)^8=(cosπ/4+isinπ/4)^8
={cos2π+isin2π}
=1
Thus ,(1-i/√2)=1
so its total value will be 2
Similar questions