(1+i/√2)^8 + (1-i/√2)^8
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(1+I/√2)^8=(cosπ/4+isinπ/4)^8
={cos2π+isin2π}
=1
Thus ,(1-i/√2)=1
so its total value will be 2
={cos2π+isin2π}
=1
Thus ,(1-i/√2)=1
so its total value will be 2
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