Question

(1 + i√3) convert to polar form?

Answer 1

Hi Mate!!!

put 1 = r Cos ( # ) and √3 = r Sin ( # )

r = 2. and # = 60°

Itz polar form is

Z = 2 ( Cos ( 60 ) + Sin ( 60 ) )

Answer 2

$\bold{\huge{Hay!!}}$

$\bold{Dear\:user!!}$

$\bold{\underline{Question-}}$

(1 + i√3) convert to polar form?

$\bold{\underline{Answer-}}$

Polar form $(1 + i \sqrt{3} ) = r(cos \theta + i \: sin \theta)$

By comparing,$r \: cos \theta = 1$

 And $r \: sin\theta = \sqrt{3}$

By adding a class of both equations,

r² = 1 + 3

r² = 4

Or. r = 2

Participation in Equation (II) by Equation (I)

$\: tan\theta = \sqrt{3} \\ \\ \theta = \frac{\pi}{3}$

So, polar forms = $2(cos \frac{\pi}{3} + i \: sin \frac{\pi}{3} )$