1. I √3 tan = 1, then find the value of
sin-cos
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Given: √3 tan θ = 1 ⇒ tan θ = 1/√3 ⇒ θ = tan-1 (1/√3) [Taking tan inverse] ⇒ θ = 30° To find value of sin2 θ – cos2 θ, substitute value of θ We get, sin2 30° - cos230° = (1/2)2 – (√3/2)2 = 1/4 - 3/4 = -2/4 = -1/2Read more on Sarthaks.com - https://www.sarthaks.com/884610/if3-tan-1-then-find-the-value-of-sin-2-cos-2
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1-root3/2
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