Question

(1+i)^4 (1+1/i)^4 write it in the form of a+ib.
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Answer 1

Answer:

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Answer 2

Answer:

=((1+i)^2)^2 (1+1/i)^4

= (1^2 + 2×1×i + i^2)^2 × (1-i)4

= ( 1+ 2i -1)^2 × ((1-i)^2)2

= (2i)^2 × (1^2- 2×1×i + i^2)^2

= 4i^2 × ( 1- 2i -1)^2

= -4 × (-2i)^2

= -4 × 4i^2

= -4 ×-4

= 16

In ( a+ ib) form

(a+ ib)= 16+ 0i

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