(1 + i)⁵ x (1-i)⁵ का मान होगा
(A)-8
(B) 8i
(C)8
(D) 32
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Answer:
Option D i.e.32
Step-by-step explanation:
Given that :-
(1 + i)⁵ x (1-i)⁵
we know that a^m×b^m=(ab)^m
=>[(1+i)(1-i)]⁵
since (a+b)(a-b)=a²-b²
Here,a=1 and b=i
=>(1²-i²)⁵
=>(1-i²)⁵
we know that i²=-1
=>[1-(-1)]⁵
=>(1+1)⁵
=>2⁵
=>2×2×2×2×2
=>32
(1 + i)⁵ x (1-i)⁵=32
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