Question

(1 - i)^6 + (1 - i)^3 =​

Answer 1

Hope it helps, if it does please mark me as brainliest.

Answer 2

$( {1 - i})^{6} + ( {1 - i})^{3} \\ \\ = ((1 - i) ^{2} ) ^{3} + 1 - 3i - 3 + i \\ \\ = ( { - 2i)}^{3} - 2 - 2i \\ \\ = 8i- 2 - 2i \\ \\ = 6i - 2$