Question

1. I am a four digit number, thousands Place is double the unit Place, tens Place is one more than hundreds Place and sum of all the digits is 13. Tell me who am

Answer 1

Step-by-step explanation:

let four digit number be abcd

here

a=2d

c=1+b

a+b+c+d=13

2d+b+1+b+d=13

3d+2b=12

if d=0(not satisfied)

d=1(not satisfied)

d=2(satisfied)

d=4(satisfied)

case 1

if d=2 then b=6

c=7 and a=4

number is 4672

case 2:-

if d=4 then b=0

c=1 and a=8

number is 8014

number 8014 only satisfies as it's sum is 13 where as 4672 doesn't satisfy as it sum is 19