Math, asked by narensoni14584242, 7 months ago



1. I am a number ,

Tell my identity !

Take me 5 times over,

And add a thirty !

To reach a century ,

I still need ten !

Who am I ? (Number)

2. A mind reading game :

Raju begins : He asks Heera to think of a number,

multiply it by 5 and subtract 5 from the product ,

Then Raju asks Heera to tell the result.

Heera says it as 10

Raju instantly declares the number which Heera had thought of it.

Now children can you find the number ?

Q2) Form Solution to Equation:

1. The solution is x = 5

form 4 different Equations

2. The solution is x = 2

form 4 different Equations​

Answers

Answered by harshch2208
0

1.)

Answer: 30

Step-By-Step Explanation:

Let the required number be x.

According to the given data, it seems to be a linear equation in x

Seven times the number gives 7x

Adding a fifty to that number gives 7x + 50 ____ (1)

To reach a triple century means the above equation needs to be equated to 300

Still forty is required for it to be equated to 300

7x + 50 = 300 – 40

7x +50 + 40 = 300

7x + 90 = 300

7x = 300 – 90 = 210

7x = 210

x = 210/7

x = 30

2.)

Answer:3

Step-By-Step Explanation:

3×5 = 15

15-5 = 10

1.)

Answer:

(x+2=7)

(x-2=3)

(x×2=10)

(x÷5=1)

2.)

Answer:

(x+25=29)

(x-3=1)

(x×12=60)

(x÷2=2)

Hope it helps:)

Pls mark as brainliest coz it took 25 mins to write it.

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