1 I f [ x²- x + 1 ,x+1 ,x+1 ,x+1] = o then x =
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∣
∣
∣
∣
∣
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x
2
−x+1
x+1
x−1
x+1
∣
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=(x
2
−x+1)(x+1)−(x−1)(x+1)=x
3
+1−(x
2
−1)=x
3
−x
2
+2
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