Question

1. (i) Find the value of sin 2 A, cos 2 A when cos A=3/5
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Answer 1

Answer:sin 2 A = 8/5 ,cos 2 A = 6/5

Step-by-step explanation:cos A =3/5

Thus , cos 2A = 2× 3/5 = 6/5 .

cos 2 A = 3/5 = B/H

By Pythagorean triple (3,4,5)

sin A = P/H = 4/5

Hence , sin 2 A = 2×4/5 = 8/5.

Answer 2

Answer:

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