Question

1. (i) In Figure (1), O is the centre of the circle. If
OAB = 40° and OCB = 30°, find AOC.
(ii) In Figure (2), A, B and Care
three points on the circle with
centre O such that AOB = 90°
and AOC = 110°. Find BAC. B
90degree ​

Answer 1

Step-by-step explanation:

A0C =360-(40+30)=270

BAC =360-(110+90)=160