Question

1. Identify the product (s) is / are formed when 1 - methoxy propane is heated with HI. Name the mechanism involved in the reaction

2. Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI.

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Answer 1

Answer:

1-methoxy propane is heated with excess HI, yields two products named as Methyl iodide and 1- iodo propane.

Answer 2

1. THE PRODUCTS FORMED WHEN 1-METHOXY PROPANE REACTS WITH HYDROGEN IODIDE ARE $CH_{3} I$ AND $CH_{3} - CH_{2} -CH_{2} -I$. IT FOLLOWS SN1 REACTION MECHANISM

2. REACTION OF 1-ETHOXYPROP-1-ENE WITH HYDROGEN IODIDE GIVES 1-IODOPROP-1-ENE AND ETHANOL.

Explanation:

1. THE PRODUCTS FORMED WHEN 1-METHOXY PROPANE REACTS WITH HYDROGEN IODIDE ARE:

• The reaction of ether with hydrogen iodide follows SN1 mechanism. It will follow the path in which more stable carbocation is formed.
• In the reaction of 1-methoxy propane with $HI$, $CH_{3} I$ and $CH_{3} - CH_{2} -CH_{2} -I$ will be formed as initially methyl iodide and propanol will be formed. But propanol will furtherly reacts with $HI$ to form iodopropane.

2. REACTION OF 1-ETHOXYPROP-1-ENE WITH HYDROGEN IODIDE:

• In the reaction of 1-ethoxyprop-1-ene with hydrogen iodide , a double bonded carbocation will be favoured as it is more stable.
• And the products will be 1-iodoprop-1-ene and ethanol.