Question

1. Identify the rate of dehydrohalogenation in the following compound when allowed to reacts
with alc. KOH:
Br
(i)
Br
(ii)
(iii)
Br
(d) iii > ii >i
(c) ii > iii > i
(a) i>ii > iii
(b) ii >i> iii​

Answer 1

Answer:

Explanation:

The ease of dehydrohalogenation of alkyl halides with alcoholic KOH is 3

0

>2

0

>1

0

this order of alkyl halides can be explained on the basis of the stability of the alkene formed after dehydrohalogenation of haloalkanes. .30

 alkyl halides on dehydrohalogenation forms more substituted alkenes, which is more stable ( and formed at faster rate) while primary alkyl halides yield least substituted alkenes, which is less stable ( and formed at a slower rate)

Answer By

Answer 2

Answer:

The rate of dehydrohalogenation follows the order:

tertiary > secondary > primary

Explanation:

According to Saytzeff's rule, during dehydrohalogenation, the alkene with the greater number of alkyl groups at doubly bonded carbon atoms is the preferred product. This implies that the most substituted alkene is more stable and is formed faster. Therefore, the alkyl halide which gives a more stable alkene must undergo dehydrohalogenation faster as compared to the one which gives a less stable alkene.

Thus, the ease of dehydrohalogenation follows the order:

tertiary > secondary > primary

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