Question

1) If 0.4g of NaoH is present in 40ml of solution. what is the molarity and normality of solution [ [moleculare mass of NaoH-40] ​

Answer 1

Answer:

Molarity = 0.25 M

Normality = 0.25 N

Explanation:

Moles = Weight / Molecular Mass

           = 0.4 / 40

           = 0.01

Volume = 40/1000 L

             = 0.04 L

Molarity = Moles / Volume(L)

             = 0.01/0.04

             = 1/4

             = 0.25 M

Normality = Molarity x n-factor

                = 0.25 x 1

                = 0.25 N

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