Question

1. If 1/a = x/(y + z), 1/b = y/(x + z) and 1/c = z/(x + y)
and x + y +Z is not equal to 10, then 2/(a + 1) + 2/(b+1) + 2/(c + 1) is​

Answer 1

Answer:

Ans=2

a=y+z/x

b=x+z/y

c=x+y/z

2/(a+1)+2/(b+1)+2/(c+1)

=2/{(y+z/x)+1}+2/{x+z/y)+1}+2/{x+y/z)+1}

=2x/(y+z+x)+2y/(x+z+y)+2z/(x+y+z)

=2(x+y+z)/(x+y+z)

=2