Question

1. If '1' is a zero of p(x) = ax^2 - 3 (a-1) x -1 , then the value of 'a' is 1 point 1 0 -1 2

Answer 1

Given: p(x) = ax^2 - 3(a-1)x - 1, x = 1

To find:  Value of a?

Solution:

• As we have given that x is equal to 1 is the zero of the given polynomial, that means 1 satisfies the given equation.

• So lets put 1 in the above equation, we get:

              a(1)^2 - 3(a-1)(1) - 1 = 0

• Now solving further, we get:

              a - 3a + 3 - 1 = 0

              2 = 2a

              a = 2

• So for x= 1, value of a is 2.

Answer:

                  So the value of a is 1 if x is equal to 1.