Question

1) If -1 is a zero of the polynomial p(x)=ax³-x²+x+4. Find the value of"a".​

Answer 1

Answer:

a=2

Step-by-step explanation:

x=-1

p(x)=ax³-x²+x+4=0

p(-1)=a(-1)³-(-1)²+(-1)+4=0

= -a-1-1+4=0

= -a+2=0

= a=2

*Hope this will help you. plz give me a thank.

Answer 2

a = 2

Step-by-step explanation:

$p(x)=ax^3-x^2+x+4$

$p(-1)=a\times(-1)^3-(-1)^2+(-1)+4$

$p(1-)=a\times-1-1-1+4$

$p(-1)=-a-2+4$

$p(-1)=-a+2$

$-a=-2$

$a=2$