Question

1) If 2Ω, 3Ω, 4Ω, 5Ω resistors are connected in parallel, then what will be the effective resistance of the circuit here?​

Answer 1

Explanation:

Rp=1/r1+1/r2+...

Rp=1/2+1/3+1/4+1/5

Rp=30+20+15+12/60

Rp=78/60

Rp=60/78

Rp=0.76923

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Answer 2

r1=2ohm

r2=3ohm

r3=4ohm

r4=5ohm

by parallel combination, we get

the effective resistance will be,

1/R = 1/(1/r1+1/r2+1/r3+1/r4)

1/R = 1/( 1/ 2 + 1/3 +1/4 + 1/5)

1/R = 1/( (30+20+15+ 12)/60 )

1/R = 1/ (77/60)

1/R = 60/77ohm

R = 77/60 ohm

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