Math, asked by mehartaj9901, 6 months ago


1. If 2 digits are
added to all odd
digits of the number
4738261 and 1 is
subtracted from all
even digits, then how
many digits will be
greater than 5 in the
new number thus
formed?​

Answers

Answered by prathamjadon22
0

Step-by-step explanation:

After subtracting 2 from each odd digit and adding 1 to each even digit, we get 5733159.

Now, second digit from right end = 5

Third digit from left end = 3

∴∴ Required sum = 5+3=8.

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