Question

1) If 2 is a zero of a Polynomial
4y² - 6y - K , Find the value of k.

2) If P(x)=x²-2 √2x+1, then find
the value of p(2√2)​

Answer 1

Step-by-step explanation:

[1]if 2 is zero of polynomial,

4(2)^2-6(2)-k=0

16-12-k=0

k=4

[2]p(2√2)=(2√2)^2-2√2(2√2)+1=8-8+1=1

therefore,p(2√2)=1

Answer 2

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