Question

1. If (-2, k) is a solution of the equation 3x + (k - 8)y = 27, then the value of k is
(a) 11,3
(b)-11,-3
(c) -11,3 (d) 11, -3
3+2y
2. If 43x + 61y = 82 and 41x - 103y = -19 then​

Answer 1

Answer:

Please find the answer below:

Step-by-step explanation:

Given (-2,k) is a solution:

It means x = -2; y = k

Given equation: 3x + (k-8)y = 27

3( -2 ) + ( k - 8 )k = 27

-6 + $k^2$ - 8k = 27

$k^2$ - 8k - 6 = 27

$k^2$ - 8k = 27 + 6

$k^2$ - 8k = 33

$k^2$ - 8k - 33 = 0

$k^2$ -11k + 3k -33 = 0

k(k-11) + 3(k-11) = 0

(k-11)(k+3) = 0

Equating both the terms to 0

k-11=0; k=11

k+3=0; k= -3

Therefore, k = 11 or -3

Hence d option is correct

Plzzzz mark me as the brainliest.