Question

1. If 22x+y = 4*-y-3 =1, then (x,y) is
(a) (-1,-2)
(b) (-1,2)
(c) (1,2)
d) (1,-2)​

Answer 1

Answer

Given 22x+y = 4x-y-3 = 1

22x+y = 22(x-y-3)

=

= 1

22x+y = 22x-2y—6

- = 2°

Comparing the powers of 2 on both sides

2x + y = 2x – 2y – 6= 0

3y = -6

y = -2y – 6

y = -2

2x+y=0=2x - 2 = 0

– =

X=1

So (x,y) = (1,-2)