Math, asked by helpmesolvethese, 1 month ago

1) If 2352 = 2a x 3b x 7c, find the values of a, b and c.
b) Given that the HCF of 2352 and 2d x 3³ × 5² x 7c is 588, find the smallest possible value
of d and e.​

Answers

Answered by sindhupriya2013polin
1

Answer:

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