Question

1. If 29x +37y= 103 and 37x + 29y = 95 then​

Answer 1

Answer:

then 29x + (37(95 - 37x))/29 = 103

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528x

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528xx = 1

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528xx = 1 therefore; 37(1) + 29y = 95

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528xx = 1 therefore; 37(1) + 29y = 9529y = 95 - 37

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528xx = 1 therefore; 37(1) + 29y = 9529y = 95 - 37y = 58/29

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528xx = 1 therefore; 37(1) + 29y = 9529y = 95 - 37y = 58/29y = 2

then 29x + (37(95 - 37x))/29 = 103841x + 37(95 - 37x) = 2987841x + 3515 - 1369x = 2987528 = 528xx = 1 therefore; 37(1) + 29y = 9529y = 95 - 37y = 58/29y = 2