Question

1) If 2x+3y=10 and 3x+2y= 15 then
find the value of (x+y)​

Answer 1

Answer:

2x+3y=10 -----1) ×3

3x+2y=15 -----2)×2

6x+9y=30

6x+4y=30

(-) (-) (-)

----------------

5y=0

y=0

x=5

(x+y)=5

Answer 2

Answer:

$5$

Step-by-step explanation:

$2x+3y=10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1)$

$3x+2y= 15 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (2)$

Multiplying equation( 1 )by 3 and (2) by 2

$6x + 9y = 30 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (3)$

$6x + 4y = 30 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (4)$

Subtracting equation 3 from 4

$\not6x + 9y = \not30 \\ \not6x + 4y = \not30 \\ \underline{- \: \: \: \: - \: \: \: \: - \: \: \: \: } \\ 5y = 0$

$\boxed{y = 0}$

Now put the value of y in equation 2

$3x + 2(0) = 15$

$3x = 15$

$x = \frac{15}{3}$

$\boxed{x = 5}$

Now,

$x + y = 5 + 0$

$= \boxed 5$