Math, asked by sanjanasood32, 2 months ago

1. If 3 men and 4 boys can do a piece of work in 12 days while 4 men and 3 boys can do the same in 10 days, the time taken by 1 man and 2 boys in doing the same type of work will be 2 3 (a) 38 — days (b) 38 — days 11 11 3 2 (c) 36— days (d) 37 = days 11 11​

Answers

Answered by brainlychallenger99
2

Answer:

hey mate , here is your answer

Correct Answer:

A) 1712 days

Description for Correct answer:

= (3men+4boys)12 days

= (4men+3boys) 10 days

= 18men+24boys=20men+15boys

= 2 men = 9 boys (i)

= 4men+3boys=(2×9)boys+3boys=21boys

= 21 boys can do a work in 10 days

= Total work = 21×10=210 units

= 2 men + 3 boys = 9 boys + 3 boys (from equation  i)

= 12 boys

= 2 boys can do 210 units in

= 21012=352=1712 days

thank you

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