Question

1. if 30 is an acute angle .
then solve the equations for alpha
1.
$2sin3 \alpha = \sqrt{3}$
2.
$tan 3 \alpha = 1$
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Answer 1

Dear friend, note that 3×alpha is acute..

Step-by-step explanation:

1.

$2 \sin(3 \alpha ) = \sqrt{3}$

$\sin(3 \alpha ) = \frac{ \sqrt{3} }{2}$

$\sin(3 \alpha ) = \sin(60)$

$3 \alpha = 60$

$\alpha = \frac{60}{2}$

$\alpha = 30$

2.

$\tan(3 \alpha ) = 1$

$\tan(3 \alpha ) = \tan(45)$

$3 \alpha = 45$

$\alpha = \frac{45}{3}$

$\alpha = 15$