Question

(1) If 3sino = 4coso then cot 0 = ?​

Answer 1

$3sin \: \theta = 4cos \: \theta \\ \frac{cos \: \theta}{sin \: \theta} = \frac{3}{4}$

$\because\frac{cos \: \theta}{sin \: \theta} = cot \: \theta$

$\therefore \: cot \: \theta = \frac{3}{4}$