Question

1. If 3x - 10° and 2x + 15° are complementary, find them.
3. If 5x + 14º and x + 46° are supplementary, find them.​

Answer 1

Here is your answer mate ..

1) 3x - 10 + 2x + 15 = 90

5x - 10 + 15 = 90

5x + 5 = 90

5x = 90 - 5

5x = 85

x = 85/ 5

x = 17

Now substitute x in the given angles

3(17) - 10 = 41

2(17) + 15 =49

so the angles are 41° and 49°

3)5x + 14 + x + 46 = 180

6x + 60 = 180

6x = 180 - 60

6x = 120

x = 20

Now substitute x in the given angles

5(20)+14=114

20+46 = 66

so the angles are 114° and 66° .

Answer 2

Answer:

1)41°,49°

2)114°,66°

Step-by-step explanation:

Sum of complementary angles are 90°

Therefore,

3x-10+2x+15=90

or, 5x+5=90

or, 5x=85

or, x= 85/5

or, x= 17

Therefore the angles are:--

3x-10=(3*17)-10

=51-10

=41°

Other angle:-

2x+15

=(2*17)+15

=34+15

=49°

Angles are 41° and 49°

Sum of supplementary angles are 180°

Therfore,

5x+14+x+46=180

or, 6x+60=180

or, 6x= 120

or, x= 120/6

or ,x= 20

Therfore the angles are:--

5x+14=(5*20)+14

=100+14

=114°

Other angle:-

x+46=20+46

=66°

Angles are 114° and 66°