Question

1. If 3x+2y=12 and xy = 6 , find the value of 9x²+4y².


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Answer 1

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According to your question you are saying that X and Y both of them has the value 6

$(3x+2y)2= \\ 2+(2y)2+2(3x)(2y)(12)2 \\ = 9x2+4y2+12(xy)144=9x2+4y2+12(6)144=9x2+4y2+72144−72=9x2+4y272=9x2+4y2</p><p>$

Answer 2

72

Step-by-step explanation:

3x+2y=12 and xy =6

3×2+2×3 =12 (xy=2×3=6 )

so, 9x²+4y² =9×4+4×9= 72