Question

1. If 4^x- 6*2^x + 8 = 0, then the values of x are​

Answer 1

Answer:

3 and - log 7 base 2

Step-by-step explanation:

1. Given 4^x -6*2^x + 8 =
2. Convert 4^x to 2^2x
3. Send 8 to other side of equation
4. then take 2^x common then we get 2^x(2^x + 6) = -1 * 8
5. Therefore 2^x = 8 that means x = 3
6. Or 2^x + 6 = -1 therefore 2^x = -7
7. hence the value of x will be - log 7 base 2
8. Therefore the values of x are 3 and- log 7 base 2

Answer 2

$\large\red{QUESTION}$

$if \: {4}^{x} - 6( {2})^{x} + 8 = 0$

$then \: \: the \: value \: of \: x \: are$

$\large\blue{ANSWER}$

${4}^{x} - 6( {2})^{x} + 8 = 0 \\ {(2 \times 2)}^{x} - (2 \times 3) {(2)}^{x} = - 8 \\ {2}^{x} (2 - 6) = - 8 \\ {2}^{x} ( - 4) = - 8 \\ {2}^{x} = \frac{ - 8}{ - 4} \\ {2}^{x} = 2 \\ {2}^{x} = {2}^{1} \\ here \: all \: the \: bases \: are \: same \: therefore \: powers \: are \: equated \\ x = 1$

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